Sunday, September 11, 2011

solve the system: 2x-5y= 3 x+ 4y = 8

We'll note the equations of the system
as:


2x-5y= 3 (1)


x+ 4y = 8
(2)


We'll solve the system using elimination method. For
this reason, we'll multiply (2) by -2:


-2x -8y = -16
(3)


Now, we'll add (3) to
(1):


 2x-5y-2x -8y=3-16


We'll
combine and eliminate like terms:


 -13y =
-13


We'll divide by -13 and we'll
get:


y =
1


We'll substitute y in
(1):


2x-5y= 3


2x =
3+5


2x = 8


We'll divide by
2:


x =
4


The solution of the system
is: {(4,1)}.

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