We'll note the equations of the system
as:
2x-5y= 3 (1)
x+ 4y = 8
(2)
We'll solve the system using elimination method. For
this reason, we'll multiply (2) by -2:
-2x -8y = -16
(3)
Now, we'll add (3) to
(1):
2x-5y-2x -8y=3-16
We'll
combine and eliminate like terms:
-13y =
-13
We'll divide by -13 and we'll
get:
y =
1
We'll substitute y in
(1):
2x-5y= 3
2x =
3+5
2x = 8
We'll divide by
2:
x =
4
The solution of the system
is: {(4,1)}.
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