Friday, November 18, 2011

Please answer the following question A traffic light of weight W hangs from two light cables; one on each side of the light. Each cable hangs at...

Assuming that there is no frictional force between the
cables supporting the traffic light and the other component of the total system
supporting the the traffic light, the sum of total tension in the cables will be exactly
equal to the force exerted by the weight of the traffic light. Further, the division of
this total tension between the two cables will depend on the the extent to which the two
cables are stretched when fitted. It is possible to fit the cables in such a way that
the tension in one cable is more than the other. In this situation, one of the two
cables will elongate or stretch more than the other under the effect of the higher
tension. However in properly fitted system care would be taken to keep the tension in
both the cables equal.


Please not that the angels of the
cable, which is flexible, has no effect on either the total tension in the two cables,
or the distribution of the tension between the two
cables.


The method of calculating tension in the answer
posted above will be applicable for calculating tension created in members of a rigid
system supporting the weight.

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