Given that v0=20 m/s and a=3 m/s^2 determine x for t = 10 s

We'll have to write the equation that describes how far an
object travels under constant acceleration.

x = v0t +
at^2/2 (1)

To determine x, we'll insert all given
information into equation:

x = (20m/s)(10s) +
(1/2)(3m/s^2)(10s)^2

We'll cancel out the seconds from the
first ratio and the s^2 from the second ratio from the right side and we'll
get:

x = 200m +
150m

x =
350m

Keeping track of the units in calculus
is helping us to detect the errors if the units don't come out
right.