EXPRESS the solution set for the inequality x^2 - 2x -3

We have the inequation x^2 - 2x -3 <=
0

x^2 - 2x -3 <=
0

=> x^2 - 3x + x - 3
<=0

=> x(x-3)+1(x-3)
<=0

=>
(x+1)(x-3)<=0

Now this is possible if either of
(x+1) and (x-3) is negative or 0.

For x+1 <=0 and
x-3 =>0

=>  x<=-1 and x=>
3

This gives no valid
values.

For x+1 =>0 and x-3
<=0

=>  x =>-1 and
x<=3

This is possible and gives us values of x
ranging from x= -1 to x=3.

The solution here
is [-1 , 3]