log x^2 = 15 + log 10

We could write 15 = 15*1 = 15*log
10

log x^2 = log 10 + 15*log
10

We'll factorize:

log x^2 =
log 10*(1+15)

log x^2 = 16*log
10

We'll use the power property of
logarithms:

log x^2 = log
10^16

We'll use the one to one property and we'll
get:

x^2 = 10^16

x1 = +sqrt
10^16

x1 = +10^8

x2 =
-10^8

For log x^2 to exist, x>0, so
the equation will have only one solution, namely x =
+10^8