It is clear that any of the 6 balls are equally likey ia
draw.
The probabilty of an event is = number chances
favouarable to the event/ total number of ways (favourable and unfavourable to the
event)
The probabilty drawing green P(G) =
2/6.
Probability of drawing red : P(R) =
2/6
So P(G or R) = P(G)+P(R) - P(G & B) = 1/6+1/6+0
= 4/6 = 2/3.
P(G & R) = 0 , as both colour balls
can not happen.
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