There are two quadratic expressions
given.
x^2+3x+2 and x^2-2x-15. To find the
factors.
1)
To find the
factors of x^2+3x+2, we split the middle term 3x into two terms in sich a way that the
product of the two split terms equal to the first and last
term.
3x is split into two terems 2x + x. Product of the
split terms = 2x*x = 2x^2. Product of the 1st and last terms = x^2 * 2 =
2x^2.
Now group the terms and find the common factors
(CF) for each
group.
(x^2+2x)+(x+2).
x(x+2)
+1(x+2). x+2 is the CF.
Take out the
CF:
(x+2)(x+1).
2)
x^2-2x-15.
-2x
= (-5x)+(3x). And (-5x)*(3x) = x^2*(-15).
Therefore
x^2-2x-15 = (x^2 -5x)+(3x-15) = x(x-5)+3(x-5) =
(x-5)(x+3).
x^2-2x-15 = (x-5)(x+1).
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