The tangent to the graph of the function f(x)=x^2+4x+2 is perpendicular to y axis . Determine the point of tangency.

The tangent line to the graph of f(x) is perpendicular to
the y axis when it is parallel to x axis.

That means that
the tangent line passes through the vertex of the function  f(x) =
x^2+4x+2.

We'll calculate the vertex of the parabola, using
the coordinates xV and yV.

xV =
-b/2a

yV = -delta/4a

We'll
identify the coefficients a,b,c.

a =
1

b = 4

c =
2

We'll substitute the coefficients into the coordinates of
the vertex:

xV =
-4/2*1

xV =
-2

yV = (4ac -
b^2)/4a

yV = (8 - 16)/4

yV =
-8/4

yV =
-2

The tangent
line, perpendicular to y-axis, is passing through the vertex of the parabola: V(-2 ,
-2).