f(x) = 3x^3 - 2x^2 + 15 find f''(1)

To evaluate the value the second derivative, in a given
point, we'll have to calculate the first derivative:

f'(x)
= (3x^3 - 2x^2 + 15)'

f'(x) = 9x^2 - 4x +
0

f'(x) = 9x^2 - 4x

Now, we'll
differentiate f'(x):

[f'(x)]' = f"(x) = (9x^2 -
4x)'

f"(x) = 18x - 4

Now, we
can calculate f"(1), substituting x by 1 in the expression of
f"(x):

f"(1) = 18*1 - 4

f"(1)
= 18 - 4

f"(1) =
14