f(x)= (x^2 -1)/(x^2 + 1)
Let
f(x) = u/v such that:
u = (x^2 -1) ==> u' =
2x
v= x^2 + 1 ==> v' =
2x
==> f'(x)=
(u'v-uv')/v^2
= (2x(x^2 + 1) - (x^2 -1)2x
]/(x^2 +1)^2
= (2x^3 + 2x - 2x^3 +
2x)/(x^2+1)^2
= 4x/(x^2 +
1)
==> f'(x) = 4x/(^2 + 1)^2
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