Tuesday, March 5, 2013

What is the energy of a 426 nm photon emitted from a light source?I came up with 2.822676 x 10 -22, but this is wrong. Answer in units of J.

The energy of a photon is given by the expression h*c / L
, where h is the Planck's constant, and c is the speed of light in m/s and L is the
wavelength of the photon in meters.


In your question, you
say the photon wavelength is 426 nm or 426*10^-9.


h is
6.626 * 10^-34 joule s


c is 2.998 * 10^8 m /
s


The energy of the photon is 6.626 * 10^-34*2.998 * 10^8/
426*10^-9


= 4.66* 10^-19
J


Therefore the solution is the energy of the required
photon is 4.66* 10^ -19 J

No comments:

Post a Comment

Comment on the setting and character of "The Fall of the House of Usher."How does setting act as a character?

Excellent observation, as it identifies how the settings of Poe's stories reflect the characters of their protagonists. Whet...