how do i solve this quadratic function x^2-6x+8=0 what i did was i factored it like : (x-4) (x-2) x=4 x=2 is this correct ?

To verify if the roots are correctly calculated, we'll use
Viete's relations.

Because we'll need the coefficients of
the quadratic, first, we'll write the equation in the general
form:

ax^2 + bx + c = 0

We'll
identify the coefficients a,b,c:

a =
1

b = -6

c =
8

These relations link the roots of the equation and the
coefficients of the equation, in this way:

x1 + x2 =
-b/a

The sum of the roots of the equation is the ratio of
the coefficients b and a.

x1*x2 =
c/a

The product of the roots is the ratio of the
coefficients c and a.

We'll substitute the coefficients
a,b,c and the calculated roots and we'll verify the
identities:

x1+x2 =
-(-6)/1

x1+x2 = 6

We'll
substitute x1 by 2 and x2 by 4:

2+4 = 6,
true!

x1*x2 = 8

2*4 =
8

Since both Viete's relations have been verified,
the calculated roots are valid.

x1 =
2

x2 =
4