What is the value of m in 4x^2+44x+m=0 so that the 2 roots are equal?show steps please

We are given the equation
4x^2+44x+m=0.

We'll use the relation that for an equation
ax^2 + bx +c = 0

The roots are given by : [-b
+sqrt(b^2-4ac)] / 2a and [-b - sqrt(b^2-4ac)]

Now as the
roots are equal it implies that sqrt(b^2-4ac) = 0

we have a
= 4 , b = 44 and c =m

substituting we
get

sqrt [ 44^2 - 4*4*m]
=0

=> 44^2 - 4*4*m
=0

=> 44^2 = 16
m

=> m = 44^2 /
16

=> m =
121

Therefore the value of m for the equation
having equal roots is 121.

[ We can see
that the root of the equation 4x^2 + 44x + 121 =0 is only -5.5 ]