Find the perimeter of the triangle whose vertices are A(0,3) B(2, 5) C (-1,2)

The perimeter of a geometric shape is a sum of the lengths
of the sides of the shape.

In our case, we have to
determine the perimeter of a triangle, so we have to calculate first the lengths of the
sides of the triangle.

The formula for calculating the
length of the side AB is:

AB = sqrt [(xB-xA)^2 +
(yB-yA)^2]

AB = sqrt
[(2-0)^2+(5-3)^2]

AB =
sqrt(4+4)

AB = 2 sqrt 2

AC =
sqrt [(xC-xA)^2 + (yC-yA)^2]

AC = sqrt [(-1-0)^2 +
(2-3)^2]

AC = sqrt 2

BC = sqrt
[(xC-xB)^2 + (yC-yB)^2]

BC = sqrt [(-1-2)^2 +
(2-5)^2]

BC = sqrt (18)

BC =
3sqrt 2

P = AB+AC+BC

P = 2
sqrt 2 + sqrt 2 + 3sqrt 2

P = 6 sqrt
2