What is x if the area of a rectangle is 16 and the length of the rectangle is x^5/(x+1) and the width is (x+1)/x^3?

given a rectangle with length (L) and width
(W)

L = (x^5)/(x+1)

W =
(x+1)/x^3

Also given that the area of the rectangle =
16

But the area A is:

A = L *w
= 16

==> (x^5)/(x+1) * (x+1)/x^3 =
16

Reduce similar
terms:

==> x^5/ x^3 =
16

But we know that: x^a/x^b =
x^(a-b):

==> x^(4-3) =
16

==> x^2 =
16

==> x=
4

Now to find the sides of the
rectangle, we will substitue with x=
4:

L = x^5/(x+1) = 4^5/(5) =
1024/5 = 204.8

W = (x+1)/x^3 =
5/4^3 = 5/64=
0.078125

==> L *W =
204.8 * 0.078125 = 16