How do you solve this? (6/xy-2/y^2)/(1/x+4/y)Perform the indicated operation and express your answer in the simplest form.

We have to solve
(6/xy-2/y^2)/(1/x+4/y)

Now
(6/xy-2/y^2)/(1/x+4/y)

making the denominator of all the
terms in the numerator the same

=> (6*y/xy^2 -
2x/xy^2)/ (1/x + 4/y)

do the same for the terms in the
denominator

=> [(6y - 2x)/xy^2] / (y/xy +
4x/xy)

=> [(6y - 2x)/xy^2] /
[(y+4x)/xy]

=> [(6y - 2x)*xy] /
xy^2*(y+4x)

cancelling the common
terms

=>[(6y - 2x)] /
y*(y+4x)

=> (6y-2x) /
y*(y+4x)

=> 2(3y - x) / y
(y+4x)

The required form is : [2*(3y - x)] /
[y*(y+4x)]