Saturday, July 6, 2013

A 0.49 kg softball is pitched at a speed of 18 m/s.The batter hits it back directly at the pitcher at a speed of 23 m/s. the bat acts on the ball...

The initial velocity of the ball is 18 m/s moving away
from the pitcher and towards the batter. The batter strikes the ball and its velocity
changes direction and is now moving at 23 m/s towards the
pitcher.


The time for the change in velocity is 0.015 sec.
Now acceleration is the rate of change in velocity. Here it is (23 - (-18 ))/ 0.015 =
8200/3  m/ s^2.


The force exerted, to result in this
acceleration is equal to mass*acceleration. As the ball is 0.49 kg, the force is 0.49 *
8200/3 = 4018/3 N.


The required force is
4018/3 N.

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