To find the equation of the line passing through (10,0)
and (-1 ,10).
Solution:
Since
the line is passing through (10,0), the line makes an intercept of 10 on y axis. So the
equation is of the form :
y = mx+c where c is the intercept
= 10. So y = mx+10 . We determine m from the fact that (-1, 10) is a point on y = mx+10
and hence the coordinates (-1,10) should satisfy y =
mx+10:
-1 = m*10 +10.
-1 = 10m
+10. Or 10m = -1-10 = -11.
Therefore m =
-11/10.
So the equation y = mx+10 becomes y = -(11/10)x+10.
Or Multiplying by 10 we get:
10y =-11x+100.
Or
11x+10y -100 = 0
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