Here we require the answer to be derived using more than
one method.
First we can see that x^2 – 4 can be written as
(x - 2)*(x + 2)
So (x^2 - 4) / (x – 2) lim
x-->2
=> (x - 2)*(x + 2) / (x-2) lim
x-->2
=> (x + 2) lim
x-->2
=> 2 + 2 =
4
Next, we can use L’ Hopital’s Rule because
substituting x = 2 in the expression (x^2 - 4) / (x – 2) yields the form 0/0 which is
indeterminate. Therefore we can use [f’(x)/g’(x)] for x=2 instead of (x^2 - 4) / (x – 2)
lim x-->2.
Now f(x) = (x^2 - 4) => f’(x) =
2x
g(x) = x-2 => g’(x) =
1
Therefore [f’(x)/g’(x)] for
x=2
=> 2*2 /
1
=>
4
As we see,
both the methods give the same result.
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