which of the following lines has a y-intercept of 5? a. 7x+2y-10=0 b. 6x-3y+15=0 c. 6x+7y-35=0i think it's all of them

To check which of the given lines has a y intercept of 5,
we'll have to put the given equations into the standard
form:

y = mx + n, where m represents the slope of the line
and n represents the y intercept.

We'll start with the
first equation:

7x+2y-10=0

To
put it into the standard form, we'll have to isolate y to the left side. For this
reason, we'll subtract 7x and add 10 both sides:

2y = -7x +
10

We'll divide by 2 both
sides:

y = -7x/2 +
10/2

y = -7x/2 +
5

The y intercept is n =
5

So, the line from the point a) has the y intercept of
5.

b) 6x-3y+15=0 

To put it
into the standard form, we'll have to isolate y to the left side. For this reason, we'll
subtract 6x and 15 both sides:

-3y = -6x -
15

We'll divide by 3 both
sides:

y = 2x +
5

We notice that the second line has the y
intercept of 5, also.

c)
6x+7y-35=0

To put it into the standard form, we'll have to
isolate y to the left side. For this reason, we'll subtract 6x and add 35 both
sides:

7y = -6x + 35

We'll
divide by 7 both sides:

y = -6x/7 +
35/7

y = -6x/7 +
5

We notice that the third
line has the y intercept of 5,
too.

So, all 3 given lines
have the y intercept of 5.