Wednesday, September 10, 2014

Which is the value of x for sinx=cosx?

For the beginning, we could give a simple answer:
x=pi/4.


Let's solve the
equation:


sin x - cos
x=0


We'll divide the equation by (cos x) and we'll
get:


sin x /cos x - 1 =0


The
ratio sinx/cosx = tanx


tan x -1
=0


We'll add 1 both sides:


tan
x = 1


x= arctan 1 + k*pi


x =
pi/4 + k*pi


pi/4=45
degrees.


We could also make the remark that if the ratio
sin x / cos x=1, the terms from numerator and denominator are equal => sin x =
cosx.


If sin x = cos x => the angles  of
the  triangle are equal, too, so, in a right angle triangle, the angles could only be =
45 degrees (the conclusion is based on fact that in a triangle, the sum of angles is 180
degrees, and one of them is 90 degrees and the other 2 are equals, so 90 +
2*x=180.


2*x=180-90


x=90/2


x=45
degrees

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