We know:
(a + b)^2 = a^2 -
2ab + b^2
Making a = x and b = 2, the above formula
becomes:
(x - 2)^2 = x^2 - 2*x*2
+2^2
= x^2 - 4x +
4
Therefore:
sqrt(x^2 - 4x +
4) = sqrt[(x - 2)^2]
= x -
2
Substituting this value of sqrt(x^2 - 4x + 4) in given
equation:
x - 2 = 0
==>
x = 2
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