Determine the slope and y intercept for d1: -2x+3y+1=0 d2: 2x-3y+1=0

We'll put the equation of d1 in the standard
form:

y=mx + n, where the
coefficients represent:

- m - the
slope

- n - y
intercept

-2x+3y+1=0

We'll
isolate 3y to the left
side:

3y=2x-1

We'll divide
by 3 both sides:

y=(2x/3) -
1/3

The standard form of the equation
is:

y=(2x/3) -
1/3

The slope of the line d1
is m = 2/3 and the y intercept is n =
-1/3.

 

We'll
put the equation of d2 in the standard form:

y=mx + n,
where the coefficients represent:

- m - the
slope

- n - y
intercept

2x-3y+1=0

We'll
isolate -3y to the left
side:

-3y=-2x-1

We'll divide
by -3 both sides:

y=(2x/3) +
1/3

The standard form of the equation
is:

y=(2x/3) +
1/3

The slope of the line d1
is m = 2/3 and the y intercept is n = 1/3.