We have to solve sqrt(x+3) + sqrt(x-2) =4 and determine
x.
First we square both the sides of the
equation.
=> [sqrt(x+3) + sqrt(x-2)]^2 =
4^2
=> [sqrt(x+3) + sqrt(x-2)]^2 =
16
=> [sqrt(x+3)]^2 +[sqrt(x-2)]^2 +
2*[sqrt(x+3)]*[sqrt(x-2)] = 16
=> x+3 + x-2
+2*[sqrt(x+3)]*[sqrt(x-2)] = 16
=> 2x +1 +
2*[sqrt(x+3)]*[sqrt(x-2)] = 16
=>
2*[sqrt(x+3)]*[sqrt(x-2)] = 15 – 2x
Square both the sides
again
=> 4*(x+3)(x-2) = 15^2 + 4x^2 –
60x
=> 4(x^2 + x -6) = 225 + 4x^2 –
60x
=> 4x^2 + 4x – 24 = 225 + 4x^2 –
60x
=> 64x=
249
=> x = 249 /
64
Therefore x = 249 /
64
No comments:
Post a Comment