Find the simultaneous solution of these system of equations: 1. 2x=4y= 6 3x-y= 2 2. 2x=3y= 8 x=8y= 17 3. x=8= 0 2x=4y= 4

We'll solve the first system using elimination
method:

2x+4y= 6 (1)

3x-y= 2 
(2)

We'll multiply (2) by 4 and we'll
get:

4(3x-y)= 4*2 

We'll
remove the brackets:

12x - 4y = 8
(3)

We'll add (1) to (3):

2x +
4y + 12x - 4y= 6+8

14x =
14

We'll divide
by 14:

x =
1

We'll substitute the value of x in (2) and
we'll get:

3*1-y= 2 

3 - y =
2

We'll subtract 3 both
sides:

-y = 2-3

-y =
-1

We'll multiply by -1 both
sides:

y =
1

The solution of the
first system is {(1 , 1)}.

We'll solve the
second system of equations using the elimination method,
also:

2x+3y= 8 (1)

x+8y= 17
(2)

We'll multiply (2) by
-2:

-2x - 16y = -34 (3)

We'll
add (3) to (1):

2x + 3y - 2x - 16y = 8 -
34

We'll combine like
terms:

-13y = -26

We'll divide
by -13 both sides:

y =
2

We'll substitute y = 2 in
(2):

x+8y= 17

x + 16 =
17

We'll subtract 16 both
sides:

x = 17 -
16

x =
1

The solution
of the second system is {(1 ,
2)}.

We'll solve the third
system of equations using the substitution method:

x-8= 0
(1)

2x-4y= 4 (2)

We'll add 8,
both sides, in (1):

x =
-8

We'll substitute x = -8 in
(2):

-2*8-4y= 4

-16 - 4y =
4

We'll add 16 both sides:

-4y
= 4 + 16

-4y = 20

We'll divide
by -4 both sides:

y =
-5

The solution
of the third system is {(-8 ,
-5)}.