We'll solve this equation y=(2x-1)/(2x+1) for x,
multiplying both sides by (2x+1):
2xy+y =
(2x-1)
We'll move all terms containing x, to the left side
and all terms in y, to the right side:
2xy-2x =
-1-y
We'll factorizeby
2x:
2x(y-1) = -1-y
We'll
divide by 2(y-1)
x =
-(1+y)/2(y-1)
Now, we'll interchange x and
y:
y = -(1+x)/2(x-1)
So, the
inverse function is:
[f(x)]^(-1) =
-(1+x)/2(x-1)
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