The lengths of 2 sides of a kite are 7.6cm & 4.3cm.Length of the shorter diogonal of the kite is 5.2cm.Use a ruler & compass to construct.Please...

A kite  is quadrilateral (convex)  in which a pair of
adjascent sides  are equal and the respective opposite pair of adjascent sides are
equal. The digagonals intersect at right angles. The shorter  diagonal is
bisected.

A quadrilateral  ABCD is a  kite AB = AD   and CD
= CB. The diagonals AC and DB intersect at right angles.

In
the given case,

AB
=AD= 4.3cm

CD = CB = 7.6
cm

The diagonal DB = 5.2
cm

Construction:

Draw  DB 
5.2cm.

 Take 4.3 cm  as radius in compass  and with D as
centre  draw  an arc  to cut the arc  with same radius drawn with centre B. Let the
intersection of arcs be A.

Now take 7.6cm radius and draw
arcs on the other side of DB with centre D and B to intersect at
C.

Now by construction DB = 5.2,  AD = AC =4.3cm ,  CD = CB
= 7.6cm. So ABCD is the required kite.