A bowling ball and a bag together cost $88. The ball costs three times as much as the bag. How much does each cost?

Let

the cost of a bowling
ball be x.

the cost of a bag be
y.

then ACCORDING TO THE STATEMENT, we will get the
following eqn

x + y =88[eqn
1]

now,the question says that ball costs 3 times as much as
bag.

which implies that, x = 3y[eqn
2]

now by using the elimination
method,

x + y =88

x = 3y which
implies that x-3y=0

now multiplying eqn 1 by 3,we
get

3x+3y=264

x-3y=0

subtracting
these two eqns, we
get

4x=264

which implies that,
x=264/4

x=66

now
x+y=88

66+y=88

y=88-66

y=22

therefore
cost of ball=x =66

cost of
bag=y=22.