If the average of 4 numbers is X, then the sum of the
differences between each of the numbers and X has to be equal to
zero.
Here we have the average as 9. Let the fourth number
to be found be D.
So we have the differences as (5-9) , (9
- 9), (12 - 9) and (D-9)
Now , (5-9) + ( 9 -9) + (12 - 9) +
(D-9) = 0
=> -4 + 0 + 3 + D - 9
=0
=> D - 10 =
0
=> D =
10.
Therefore the fourth number is
10.
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