In an unbiased coin chance of getting a head = chance of
getting atail = 1/2
The probability of getting x heads in n
tosses of the coin is given by
P(x) =( nCx
)(1/2)^x)(1/2)^(n-x).
Since n =100, probability of getting
hed s 55 or more = p(x=55)+P(x>55) = P(x > =55) = Summation P(x) for x =55
to 100.
Summation (100Cx) ((1/2)^x) (1/2)^(100-x) =
(100Cx)(1/2^100
=0.18410080866 from
tables.
Probability of number of hesds(= x ) between 40
and 60 is
P( 40 < x<60) = summation 100Cx
(1/2)^100. for x= 41, 42, 43,...60.
= P(x <= 59) -
P((x< = 40) = 0.977155 60331 - 0284439668 = 9511120662 from
tables.
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