h(x) =( 5-x)/the square root of 5x-125what is largest possible domain

To find the largest domain of h(x) =
(5-x)/sqrt(5x-125)

The lthe domain of h(x) =
(5-x)/sqrt(5x-125) is the set of all x for which h(x) is defined and
real.

The expression (5-x)/ sqrt(5x-125) has the
denominator sqrt(5x-125).

When 5x-125 = 0,   x = 125/5 =
25.

So the expresion (5-x)/sqrt(5x-125) becomes (5-25)/0
which is not defined.

So x = 25  cannot be in the
domain.....(1)

Also sqrt(5x-125) is not real when 5x
< 125. Or x < 125/5 = 25.

Therefore the
domain cannot take vaues x < 25. (2)

So combining
the (1) and (2) , we see that the domain  of  h(x) = (5-x)/sqrt(5x-125) is x >
25. Or  the domain of x  is  (25 , infinity) wher 25 is not
included.