Yes, it is possible to solve the equation, using
derivative of the function associated to the
expression:
f(x) = x -
sinx
The function is a continuous function, formed by
elementary functions as the linear one,x , and the trigonometrical one, sin x, so we can
calculate it's derivative.
f'(x) = (x -
sinx)'
f'(x)=1-cosx
We notice
that the first derivative is an increasing function.
(
-1<cosx<1), so the difference 1 -cos x>0 =>f(x)>0, so
f(x) is one-one function.
We can also do a very simple
calculus:
f(0)=0-sin0=0-0=0.
Because
f(x) is an one-one function, x=0 is the only solution for the
equation x-sinx=0.
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