Solve the problem.An open box is to be formed from a rectangular sheet of tin 20*32 in cutting equal squares , x in on a side , from the four...

The sides of the rectangular sheet are 20 in. and 32 in.
in length.

Let the sides of the square which are cut be
x.

Once they are cut the side that was initially 20 in.
long is now 20- 2x in. long. And the side that was 32 in. long remains 32-2x in.
long.

Now the sides are turned up to make a
box.

The base of the box has dimensions 20 - 2x and 32- 2x
in. And the height of the box is x in.

Therefore the volume
of the box is (20- 2x)(32-2x)(x)

Or expressed as a function
of x :

V(x) = 4x(10- x)(16-x)
in^3