We know that f(x) and g(x) are asymptotic if f(x)/g(x) =
1 as x--> infinity. Or f(x) - g(x) = k a constant as x -->
infinity.
We consider the function y(x) =
(3x^2+5x+5)/x
Let f(x) =
3x+5.
Then y(x) - 3x+5 = (3x^2+5x+5)/x - 3x+5 =
{3x^2+5x+5-3x^2-5x) = 5/x > 0 x for all x ant 5/x = 0 as x -->
infinity.
Therefore 3x+1 is the oblique
asymptote.
Also for a vertical asymptote, at x= a , y
should be infinite.
So at x = 0, y(x) = (3x^2+x+5)/x =
3x+1 +5/x is infinte as 5/x = ifinity as x-->
0.
Threfore 3x^2+1 and y axis are the asmptotes for the
curve y = (3x^2+x+5)/x.
No comments:
Post a Comment