To solve for x in 2log5 +3logx
=2
Solution:
2log5 = log 5^2
=log25, as n*log b = logb^n
3logx =
logx^3
and 2 = lof10^2 = log
100.
Replacin in the given
equation:
log25*logx^3 = log
100.
log(25x^3) = log 100. Taking
antilogarithms,
25x^3 =
100
x^3 = 100/25 = 4
x^3 = 4.
Take the cube root.
x = 4^(1/3) is the real
solution.
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