(1)
The given series of
numbers is:
1/2, 1/4, 1/8,
...
This can also be represented
as:
1/(2^1), 1/(2^2), 1/(2^3),
...
Thus the nth term of the series can be represented as
(1/2^n).
Using this formula for the nth term, the first 5
terms of the series become:
1/2, 1/4, 1/8,1/16, 1/32,
...
(2)
The given
series of numbers is:
-3, 6, -9, 12,
...
This can also be represented
as:
(-1^1)(3*1), (-1^2)(3*2), (-1^3)(3*3),
(-1^4)(3*4),...
Thus the nth term of the series can be
represented as (-1^n)(3n).
Using this formula for the nth
term, the first 6 terms of the series become:
-3, 6, -9,
12, -15, 18, ...
No comments:
Post a Comment