Find the distance between the line y+2x -5= 0 and the point (1,3).

The distance from a point to a given lineis the
perpendicular to that line.

We have to determine the
equation of the line that passes through the given
points.

We'll note the given line by l:y+2x -5=
0 

Because we don't know the coordinates of the
intercepting point of 2 perpendicular lines, we'll calculate the distance using the
formula:

d(point,l)=|(3+2-5)|/sqrt[(2)^2+(-5)^2]

d(point,l)
= 0/sqrt
29

d(point,l) =
0

So,
there is no distance between the point and the given line, meaning that the point is
located on the line.

We'll
prove that by substituting the coordinates of the point in the eq. of the line, y+2x -5=
0.

3 + 2*1 - 5 = 0

0 = 0
q.e.d