a4 = 19, a1 = 10 to find a10 of the
AP.
Solution:
For an
Arithmetic progression, the rth term ar = a1+(r-1)d, where d is the common difference.
So,
a4 - a1 = a1+3d-a1 =
3d
Here a4 -a1 = 19- 10 = 9
3d
=9
d =3.
S0 a10 = a1+(10-1)d =
10 +(10-1)*3 = 37
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