Tuesday, May 21, 2013

log 5x - log 7 = log 32 + 5log5

log 5x - log 7 = log 32 + 5log
5


Let us rewrite 32 =
2^5


==> log 5x - log 7 = log 2^5 + 5log
5


==> log 5x - log 7 = 5log 2 + 5log
5


We have 5 is a common
factor:


==> log 5x - log 7 = 5(log 2 + log
5)


Now we know that:


log a +
log b = log a*b


log a - log b = log
(a/b)


==> log (5x/7) = 5log
(2*5)


==> log (5x/7) = 5 log
10


But, log 10 = 1


==>
log (5x/7) = 5


==> 5x/7 =
10^5


==> 5x =
7*10^5


==> x= (7*10^5)/5= 14*10^4=
140000


==> x= 140,000

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