What are the x-intercepts of y = 2x^2 - 3x – 20

The x intercepts are, in fact, the roots of the
equation:

2x^2 - 3x – 20 = 0 (when the graph of the
y function is intercepting x axis).

Now, all we have to do
is to solve the equation.

Because it's a quadratic, we'll
apply the quadratic formula:

x1 = [-b+sqrt(b^2 -
4ac)]/2a

x2 = [-b-sqrt(b^2 -
4ac)]/2a

We'll identify a, b and c, which are the
coefficients of the function:

y = ax^2 + bx +
c

y = 2x^2 - 3x – 20

a =  2, b
= -3, c = -20

Now, we'll calculate the
roots:

x1 = [-(-3) + sqrt(9
+160)]/2

x1 =
(3+13)/2

x1 =
8

x2 =
(3-13)/2

x2 =
-5

So, the x intercepts are x1
and x2.