Thursday, May 28, 2015

What is the tension in units of N of the string in the scenario below if the acceleration of gravity is 9.8 m/s^2?An air puck of mass o.257 is tied...

The centripetal force of a rotating body is given by
mv^2/r. Where m is the mass of the body, r is the radius of the circle it is rotating in
and v is the velocity it is moving at.


Here we have the
mass = 0.257 kg (I assume it is kg), the radius 0.78 m, but the velocity is not
specified. Let's assume it is V.


Now the centripetal force
is due to the mass tied at the end of the string and is equal to weight of the body or
1.51*9.8 N.


So we have 0.257*V^2/0.78 =
1.51*9.8


=> V^2 =
1.51*9.8*7.8/0.257


=> V^2 =
449.1


=> V = 21.19
m/s


So the puck rotates at 21.19
m/s


The force due to weight of the body is
the tension in the string, so the tension is equal to 9.8*1.51 = 14.798
N

No comments:

Post a Comment

Comment on the setting and character of "The Fall of the House of Usher."How does setting act as a character?

Excellent observation, as it identifies how the settings of Poe's stories reflect the characters of their protagonists. Whet...