We'll add 1 both sides:
log
10 x - 1 + 1 = log 10 + 1, but log 10 = 1
log 10x = log 10
+ log 10
We'll use the product property, for the sum from
the right side:
log 10x = log
10*10
log 10x = log
100
Because the bases of the logarithms are matching, we'll
use the one to one property:
10x =
100
We'll divide by 10 to isolate
x:
x = 10 > 0
Since x
is positive, the equation has the solution x=10.
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