Friday, August 14, 2015

Find the antiderivative of x^1/2/(x-1)

F(x) is such a function such as dF/dx =
f(x).


We'll calculate the function F(x) integrating the
given function:


Int f(x)dx = F(x) +
C


Int sqrtx dx/(x-1)


We'll
write the denominator of the function as a difference of
squares:


x - 1 = (sqrtx - 1)(sqrtx +
1)


We'll re-write the
integral:


Int sqrtx dx/(sqrtx - 1)(sqrtx +
1)


We'll add and subtract 1 to the
numerator:


Int (sqrtx + 1 - 1 )dx/(sqrtx - 1)(sqrtx +
1)


We'll re-group the terms in a convenient
way:


Int (sqrtx + 1 - 1 )dx/(sqrtx - 1)(sqrtx + 1) =
Int(sqrtx + 1)dx/(sqrtx - 1)(sqrtx + 1) - Int dx/(sqrtx - 1)(sqrtx +
1)


We'll simplify and we'll
get:


Int (sqrtx + 1 - 1 )dx/(sqrtx - 1)(sqrtx + 1) = Int dx
- Int dx/(x-1)


Int f(x)dx = x - ln|x-1| +
C


F(x) = x - ln|x-1| +
C

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