Given that 3x+3y-1=0 and x-4y+4=0 calculate y intercepts and the slopes of the lines .

We'll put the equation of the given lines in the standard
form:

y=mx + n, where the
coefficients represent:

- m - the
slope

- n - y
intercept

 3x+3y-1=0

We'll
isolate 3y to the left side:

3y =
-3x+1

We'll divide by 3 both
sides:

y=(-3x/3) + 1/3

The
standard form of the equation is:

y = -x +
 1/3

The slope of the first
line is m1 = -1 and the y intercept is n1 =
1/3.

We'll put the next given equation in
the standard form:

y=mx + n, where the
coefficients represent:

- m - the
slope

- n - y
intercept

x-4y+4=0

We'll
isolate -4y to the left side:

-4y =
-x-4

We'll divide by -4 both
sides:

y=(-x/-4) + (-4/-4)

The
standard form of the equation is:

y = (x/4) +
1

The slope of the second line
is m2 = 1/4 and the y intercept is n = 1.