The distance d of (x1,y1) and(x2,y2) is given
by:
d^2 =(x2-x)^2 +
(y2+y1)^2.
Since PR = QR and R is on Y axis, the x
coordinate of R is 0 and so the the coordinates of R are of the form
(0,k)
Therefore PR= QR => PR^2* QR^2.
Or
(0-3)^2+(k-7)^2 = (0-11)^2+(k- -
6)^2
9+k^2-14k+49 = 121
+k^2+12k+36
-(14+12)k = 121+36 -9-49 =
99
k = 99/-26 = -(99/26)
The
the coordinates of R = (0, -99/26)
No comments:
Post a Comment