Sunday, February 21, 2016

1. If know x = 112^{o}: find cosx ; sinx? 2. Find sin1^{o}.

1)


If x= 112 degree = 90+22
degree= 180-68 degree.


sin(90+22) = sin (180 - 68) = sin68
=  0.9272 using tables.


For approximation, sinx =
4x(180-x)/(40500-x(180-x), for 0<x<180
only.


= 4*112*68/(40500-112*68) = 0.9264, cosx =
sqrt(1-sin^2 x) = -0.3765


cos112 = cos(180-68) = -cos68 =
-0.3746 using tables


2)


sin 1
degree  = sin (pi/180 radians) = sin (0.1745 radians) = 0.017452, as for small x in
radians, sinx --> x.

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