x^4-4x^2-32 = 0 To solve for
x.
Solution:
This is a
quadratic equation in x^2. So we solve it by factoring as a
quadratic.
t^2-4t-32 = 0, where t=
x^2
t^2-8t+4t-32 =
0
t(t-8)+4(t-8) = 0
(t-8)(t+4)
= 0
t-8 = 0 or t+4 = 0
t-8= 0
gives x^2 = 8 , x = +or- sqrt8 = 2sqrt2 or -2sqrt2
t+4 = 0
gives x = sqrt(-4) = +or-2i
So the solution set is {
-2i,2i, -2srt2, 2srt2}
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