We know that when two resistors a and b are connected in
series the equivalent resistance of the system is a + b. Now we are given the three
resistors as 10 ohm, 25 ohm and 20 ohm. When they are connected in series the equivalent
resistance is 10 + 20 + 25 = 55 ohm. When the combination is connected across a voltage
V the energy consumed is V^2/ R = V^2/ 55.
Now, when two
resistors a and b are connected in parallel the equivalent resistance is given as (1/a +
1/b) ^ (-1). So for the three resistors connected in parallel the equivalent resistance
is (1/10 + 1/20 + 1/25) ^-1 = (0.1 + 0.05 + 0.04) ^-1 = 1/ 0.19 = 5.26 ohm. Now the
energy consumed is V^2 / 5.26
So we can see
that the resistors in parallel consume more energy than they do when they are connected
in series.
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