Bring the equation of the line 3x-4y-12=0 to the intercept form and find the intercept on the axis .

3x-4y-12 = 0. To bring to the intercept
form.

Solution:

There are two
types of intercept forms:

(i) slope and  intercept  form: y
= mx+c , where m is slope and c is y
intercept.

The given equation is 3x-4y -12 = 0.
Add 4y.

3x-12 = 4y Divide by
4:

3x/4 -12/4 = y. Or

y =
(3/4)x-3.

(ii) Double ntercept form: x/a +y/b =1, where a
and b are the intercepts on x and y axis.

Given equation :
3x-4y  -12 = 0. Add 12.

3x-4y = 12. Divide by
12:

3x/12 -4y/12 = 1. Re write
as:

 x / (12/3)  + y/(12/-4) = 1.
Or

x/4 + y/(-3) = 1.

Therefore
3x-4y -12 has the double intercept form x/4 +y/(-3) = 1.

So
4 is x intercept and -3 is y
intercept.

x