What is the prime factorization of 525 in exponential form?

To find the prime factors of a number, start by dividing
until you cannot divide any other numbers into any
factors.

For 525, begin by dividing by 5 this leave 105 x
5

105 can be further factored by dividing by 5 again = 21 x
5

21 can be further factored to 3 x
7

At this point nothing can be be further factored.  The
factors of 525 are 5, 5, 7, and 3.  

To write this answer
in exponential form, you need to write any factors that appear more than once as an
exponent. In this case the only factor that appears more than once are the 5s that
appear twice.

your final answer will be 5^2 x 7 x
3